Question

Mth term of arithmetic progression series 2,4,6-—------- is
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Answer 1

Answer:

hope you got your answer

Answer 2

$Given \: arithmetic \: progression :$

$2,4,6, \ldots$

$First \:term ( a = a_{1}) = 2$

$Common \: difference (d) = a_{2} - a_{1}$

$= 4 - 2$

$= 2$

/* We know that */

$\boxed{\pink{ n^{th} \:term (a_{n}) = a + (n-1)d }}$

$Here , a = 2 , \: d = 2 \: and \: n = m$

$\red{ m^{th} \: term (a_{m}) }$

$= 2 + ( m - 1 ) \times 2$

$= 2 + 2m - 2$

$\green { = 2m }$

Therefore.,

$\red{ Required \: m^{th} \: term\: of \: A.P }$

$\green { = 2m }$

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