much was invested in each ?
An amount of 65,000 is invested in three investments at rates of 6%, 8% and 9% per
annum respectively. The total annual income is ? 4800. The income from the third
investment is 600 more than the income from the second investment. Using matrix
algebra, determine the amount of each investment. [Delhi Univ. B.Com. (H) 1995)
Answers
Answered by
2
Answer:
30,000
15,000
20,000
Step-by-step explanation:
Principal Amount = 65000
Let R₁ = 6%, R₂ = 8%, R₃ = 9%
Let I₁, I₂, and I₃ be income from each investment.
Total Investment Equals,
I₁ + I₂ + I₃ = 65,000 A
Total Annual Income Equals,
6I₁/100 + 8I₂/100 9I₃/100 = 4800
6I₁ + 8I₂ + 9I₃ = 480000 B
Income From 3rd Investment Is 600 More Than 2nd Investment,
9I₃/100 = 8I₂/100 + 600
9I₃ = 8I₂ + 60000 C
From A, B and C
I₁ = 30,000
I₂ = 15,000
I₃ = 20,000
Thank You.
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