Question

much was invested in each ?
An amount of 65,000 is invested in three investments at rates of 6%, 8% and 9% per
annum respectively. The total annual income is ? 4800. The income from the third
investment is 600 more than the income from the second investment. Using matrix
algebra, determine the amount of each investment. [Delhi Univ. B.Com. (H) 1995)​

Answer 1

Answer:

30,000

15,000

20,000

Step-by-step explanation:

Principal Amount = 65000

Let R₁ = 6%, R₂ = 8%, R₃ = 9%

Let I₁, I₂, and I₃ be income from each investment.

Total Investment Equals,

I₁ + I₂ + I₃ = 65,000                                                               A

Total Annual Income Equals,

6I₁/100 + 8I₂/100 9I₃/100 = 4800                                

6I₁ + 8I₂ + 9I₃ = 480000                                                       B

Income From 3rd Investment Is 600 More Than 2nd Investment,

9I₃/100 = 8I₂/100 + 600

9I₃ = 8I₂ + 60000                                                                 C

From A, B and C

I₁ = 30,000

I₂ = 15,000

I₃ = 20,000

Thank You.