Question

Mudit stands on a point A which lies on a line segment joining the point P(6, -6)
and Q(-4,-1) in such a way that
a =
Find the co-ordinates of point A.​

Answer 1

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the co-ordinates of point A.

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p(6,-6)=(x1,y1) & Q(-4,-1)=(x2,y2)

USE DISTANCE FORMULA,

x1+x2/2 ____ OR ___ y1+y2/2

=6+(-4)/2_______ OR _____ ( -6)+(-1)/2

=2/2 _____ OR ____ -7/2

=1 ________ OR ______ -3.5

SO,

the co-ordinates of point A (1,-3.5)

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Answer 2

Mid point of line  $PQ$  is $A$  which have coordinate      

 $A(x,y)=(1,-3.5)$

Step-by-step explanation:

Given,

coordinates of  P

$P(6,-6)=P(x_{1},y_{1})$               $x_{1}=6,y_{1}=-6$

Coordinates of Q

$Q(-4,-1)=P(x_{2},y_{2})$             $x_{2}=-4,y_{2}=-1$

Let coordinates of A

$A(x,y)$

Formula for mid point

$x=\left ( x_{1}+x_{2} \right )/2$              $y=\left ( y_{1}+y_{2} \right )/2$

$x=\left ( 6+\left ( -4 \right ) \right )/2$             $y=\left ( -6+\left ( -1 \right ) \right )/2$

$=\left ( 6-4 \right )/2$                        $=\left ( -6-1 \right )/2$

$=2/2$                                  $=-7/2$

$x=1$                                $y =-3.5$

We find the coordinates of A from above solution

             $A(x,y)=(1,-3.5)$