Mugdha distributed (4x^3 + 2x^2 + 3x) sweets among 2x children. Find the sweets obtained by each child.
Answers
Answer:
2x^2+x+3/2
Step-by-step explanation:
4x^3+2x^2+3x/2x=2x^2+x+3/2
Given : Mugdha distributed (4x³ + 2x² + 3x) sweets among 2x children.
To Find : the sweets obtained by each child.
Solution :
Let say Sweet obtained by each child = N
Child = 2x
Total Sweet obtained = N * 2x
Total sweets distributed = (4x³ + 2x² + 3x)
Equating Both
=> N * 2x = (4x³ + 2x² + 3x)
=> N * 2x =x (4x² + 2x + 3)
=> N * 2 = 4x² + 2x + 3
Dividing by 2 on both sides
=> N = 2x² + x + 3/2
Sweets obtained by each child = 2x² + x + 3/2
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