Question

MUI
17. How many moles of lead (II) chloride will be formed
from a reaction between 6.5g of PbO and 3.2 g of
HCI?
[AIPMT (Prelims)-2008]
(1) 0.029
(2) 0.044
(4) 0.011
(3) 0.333​

Answer 1

Answer:

0.029

Explanation:

PbO+2HCl→PbCl²+H²O

Atomic mass of PbO = 207 + 16 = 223

Atomic mass of HCl = 36.5

Moles of PbO =

223

6.5

= 0.029 moles

Moles of HCl = 36.5 / 3.2

= 0.088 moles

From the above chemical equation, we see that PbO is the limiting reagent.

∴ 1 mole of PbO gives 1 mole of PbCl²

0.029 moles of PbO forms 0.029 moles of PbCl²