mujhe answer dijiye
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Right .
Step-by-step explanation:
Let the sides of triangle is a
in ∆ABC AD perpendicular to BC
AB² = AD² + BD²
4a² -a² = AD²
√3 a = AD
Area of ∆ ADB = 1/2 × b × h
= 1/2 × a × √3 a
= √3 a²/ 2
Area of ∆ ABC = s = a +b+c/2
2a +2a +2a / 2
= 3a
Herons formula = √ s(s-a)(s-b)(s-c)
√ 3a( a)(a)(a)
√3 a²
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