Mukesh throws stone vertically upwards with a a velocety of 42 m/s which reaches a height of 90m. what will be the tolal time by the stone to reach the Surface of the Earth?
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Answer:
Initial Velocity u=40
Final velocity v=0
Height, s=?
By third equation of motion
v
2
−u
2
=2gs
0−40
2
=−2×10×s
s=
20
160
⇒s=80m/s
Toatal distance travelled by stone = upward distance + downwards distance =2×s=160m
Total Displacement =0, Since the initial and final point is same.
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