Question

. Mukesh walks around a circular park AOB of radius 42 cm. Calculate:

1) The distance and displacement from point A to B.

2) The distance and displacement from point A to A in two rounds.​

Answer 1

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Answer 2

Concept:

• Distance is the length of the total path taken by an object during its motion
• Displacement is the shortest distance between the initial and final points of the motion of an object
• Circumference of a circle = 2πR

Given:

• The radius of the circular park R= 42 m
• Mukesh walks from A to diametrically opposite point B
• Mukesh also walks 2 rounds starting and ending at the same point A

Find:

• The distance and displacement from point A to B.
• The distance and displacement from point A to A in two rounds.

Solution:

1) A to B are diametrically opposite points, so Mukesh travels along the semicircular path

Distance = length of the curve of semicircle = πR

Distance = π* 42 = 42π m

Displacement = diameter of the circle = 2R = 2*42 = 84m

2) Two rounds are covered, so the path covered is two times the circumference of the circle

Distance = 2*2πR = 4πR = 4π*42 = 168 π m

Mukesh ends up at the same point as his starting point, so the net displacement is 0.

1) The distance and displacement from point A to B are 42π m and 84 m respectively.

2) The distance and displacement from point A to A in two rounds are 168 π m  and 0 respectively.

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