Question

Mukesh work twice as fast as Manish. If Manish alone
can complete work in 6 days. So time taken by both of
them together to finish the work is.
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Answer 1

• $let \: the \: mukesh \: be \: x \\ let \: manish \: be \: \: y \\ x = 2 \times y.......1eq. \\ y = 6 \: \: \: putting \: in \: 1 \\ x = 2 \times 6 = 12 \\ x = 12 \\ both \: complete \: work \: {x + y} \\ 6 + 12 = 18 \\ answer \: is \: 18days.$

Answer 2

They can finish the work together in 2 days.

Step-by-step explanation:

Let the work done by Mukesh represents by 'k' and the work done by Manish represents by 'n'.

Mukesh work twice as fast as Manish.

Manish alone can complete work in 6 days.

So Mukesh alone can complete work in half time = 3 days

Work done by Manish in one day =

Work done by Mukesh in one day =  $\frac{1}{3}$

Work done by together in one day =  $\frac{1}{3} +\frac{1}{6}$

                                                         $=\frac{2+1}{6}$

                                                          $=\frac{3}{6}$

                                                          $=\frac{1}{2}$

They can finish the work together in 2 days.

Learn more work time problem : https://brainly.in/question/15198417