Math, asked by ravariyarit, 1 year ago

Muktha had rupees 12 on 4th Jan 2018 see saved Rupees 15 after the day everyday she saved rupees to more than the earlier than including De the savings upto up to on 30 December 2018 how much total amount did she saved​

Answers

Answered by snehans1153
1

Answer:

On 4 jan 2018 had ₹12 each day she add ₹15

Therefore,

Ap formed is :

12,27,42..

Here a=12, d=15, n=365-4=361

(as 3 days are spent and 31st of dec is not added)

S361=361/2(2(12) + (361-1)15

S361=361/2(24+360×15)

=361/2(24+5400)

=361/2(5424)

=361×2712

=979032

Thus ₹979032 is saved by her till 30dec2018

Step-by-step explanation:

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