Multi Choice Type Question
Marks : 1 Negative Marks : 0
A, B, C, D and E play a game of cards. A says to B, "If you give me
three cards, you will have as many as E has and if I give you three
cards, you will have as many as D has." A and B together have 10
cards more than what D and E together have. If B has two cards
more than what C has and total number of cards be 133, how
many cards does B have?
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Answer:
Clearly, we have :
B - 3 = E ...(i)
B + 3 = D ...(ii)
A+B = D + E+10 ...(iii)
B = C + 2 ...(iv)
A+B + C + D + E= 133 ...(v)
From (i) and (ii), we have : 2 B = D + E ...(vi)
From (iii) and (vi), we have : A = B + 10 ...(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B - 2) + 2B = 133 ⇔ 5B = 125 ⇔ B = 25.
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