Math, asked by nellaprasad, 7 hours ago

Multifaly (6202-5x + 3) and (3x2 + 7 x-3)

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Answered by advaithshenoy2010

Answer:

Doubtnut

(6x2 – 5x + 3) by (3x2 + 7x – 3) ... `3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11 ; x!=3/5,-1/7` ... 7x - 5x ge 3 + x. play · Solve the equation (3x^4+x^2-2x-3).

Missing: (6202- ‎| Must include: (6202-

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Multifaly (6202-5x + 3) and (3x2 + 7 x-3)​

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Multifaly (6202-5x + 3) and (3x2 + 7 x-3)