Math, asked by gurjit99, 11 months ago

multiple (2ab+3bc+8ca) by 7abc

Answers

Answered by vaibhavlspise2001

3

Answer:

Step-by-step explanation:

(2ab+3bc+8ca)*7abc

we get

14a^2b^2c+21ab^2c^2+56a^2c^2b

thank you

Answered by piyush0113

2

Answer:

(2ab+3bc+8ca)7abc

=2ab*7abc+3bc*7abc+8ca*7abc

=14a^2b^2c+21ab^2^c+56a^2c^2b

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