multiple (2y²-1)×(y²-2y³+3y)
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0
Answer:
6y-y^2+8y^3+2y^4-4y^5 so yur ans
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Answer:
(2y+1)(y²-2y³+3y)
= 2y(y²-2y³+3y)+1(y²-2y+3y)
= 2y³-4y⁴+6y²+y²-2y+3y
= -4y⁴+2y³+7y²+y
HOPE IT HELPED YOU.
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