multiple (7√2-5√3) from (3√2-6√5)
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Multiply (√3—√7+2√5) and (√3+√7–2√5)
={√3—(√7–2√5)} x. { √3+(√7–2√5)}.. arranging the terms
=(√3)^2—(√7–2√5)^2..((a--b)(a+b)=a^2—b^2)
=3—((√7)^2–2*√7*2√5+(2√5)^2)..((a -b)^2=a^2–2ab+b^2))
=3—(7+20–4√7*√5)
=3—(27–4√35)
=3–27+4√35
=-24+4√35
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