Question

Multiple Choice Questions (MCQs)
2
A bus increases its speed from 36 km/h to 72 km/h in 10 seconds. Its acceleration is :
(9) 5 m/s2
(b) 2 m/s2
(c) 3.6 m/s2
(d) 1 m/s2​

Answer 1

Answer:

1 m/s^2

Explanation:

v2= 72kmph = 20m/s

v1= 36kmph= 10m/s

time= 10sec

a= (v2-v1)/t

=> a = $\frac{20-10}{10}$ = 1m/s^2

Answer 2

Given : A bus increases its speed from 36 km/h to 72 km/h in 10 seconds.

　

To find : What is its acceleration?

　

Using formula :

★ Acceleration = Final velocity - Initial velocity/Time.

　　　　　　　　　　or

★ a = v - u/t.

　

Calculations :

→ Velocity = 36 km/hr

　

Converting km/hr into m/s :

→ Velocity = 36000 m/3600 s

→ Velocity = 10 m/s

　

→ Acceleration = 10 - 0/10

→ Acceleration = 10/10

→ Acceleration = 1 m/s²

　

Therefore, 1 m/s² is the required acceleration.