Question

Multiple choice questions
Q12: If the displacement of an object is proportional to square of time, then
object moves with:
(a) Uniform velocity
(b) Uniform acceleration
(c) Increasing acceleration
(d) Decreasing acceleration​

Answer 1

Answer:

A)

Explanation:

x=kt^2 given ( square of velocity propotional to time t here

diffrentiate it

v=2kt or v=bt ( where b is new arbituary constant )

since v is uniform as linear function of t

so A)

EXTRA FACTS : Accelaration is constant here as a=b here which is constant

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Answer 2

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Object moves with Uniform Acceleration.

EXPLANATION

Displacement is proportional to square of time

⠀⠀⠀⠀⠀⠀⠀⠀⠀s ∝ t²

⠀⠀⠀⠀⠀⠀⠀⠀⠀s = kt²

⠀⠀⠀ , where k is constant of proportionality.

Differentiating Displacement , we get Velocity (v)

⠀⠀⠀⠀⠀⠀⠀ ds/dt = 2kt

Differentiating Velocity , we get Acceleration (a)

⠀⠀⠀⠀⠀⠀ dv/dt = 2k = constant.

ᗇ So, object moves with Constant Acceleration.