Math, asked by AishikRay100, 5 months ago

Multiple i) (5x²+4x-2) by (3-x-4x²)

Answers

Answered by Ҡαηнα

3

Answer:

Step-by-step explanation:

$(5x^{2} +4x-2)$ × $(3x-x-4x^{2} )$

$[5x^2$ × $(3x-x-4x^2)]$ $+[4x$ × $(3x-x-4x^2)]$ $-[2$ × $(3x-x-4x^2)]$

$[15x^3$ $-5x^3-20x^4]$ + $[12x^2-4x^2-16x^3]$ - $[6x-2x-8x^2]$

$(10x^3-20x^4)+(8x^2-16x^3)-(4x-8x^2)\\10x^3-20x^4+8x^2-16x^3-4x+8x^2\\-20x^4-16x^3+10x^3+8x^2+8x^2-4x\\-20x^4-6x^3+16x-4x$

Answered by haramrahero1234

2

Step-by-step explanation:

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