multiple of first ten numbers
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It is an interesting question but the answer lies in how well u implement it and not to panic during the test time…
10 multiples of
1:1,2,3,4,5,6,7,8,9,10
2:2,4,6,8,10,12,14,16,18,20
And so on but if you observe here,
If 2 is taken out from the series we get,2(1+2+3+4+5+6+7+8+9+10)
Therefore the series comes out to be
S=1(1+2+3+4+…..+10) +2(1+2+3+4+5+6+…+10)+3(1+2+3+4+5+6+…+10)+4(1+2+3+4+5+6+…+10)+5(1+2+3+4+5+6+…+10)+5(1+2+3+4+5+6+…+10)+…….+10(1+2+3+4+5+….+10)
S=(1+2+3+4+5+6+7+8+9+10)(1+2+3+4+5+6+7+8+9+10)
S=((10*11)/2)*((10*11)/2)
S=(110*110)/4
That is the sum comes out to be S
Average is S/100 since there are total 100 numbers
This implies
A=(110*110)/(4*100)
A=121/4
Which is your required answer
I hope my answer is helpful
Thank you.
10 multiples of
1:1,2,3,4,5,6,7,8,9,10
2:2,4,6,8,10,12,14,16,18,20
And so on but if you observe here,
If 2 is taken out from the series we get,2(1+2+3+4+5+6+7+8+9+10)
Therefore the series comes out to be
S=1(1+2+3+4+…..+10) +2(1+2+3+4+5+6+…+10)+3(1+2+3+4+5+6+…+10)+4(1+2+3+4+5+6+…+10)+5(1+2+3+4+5+6+…+10)+5(1+2+3+4+5+6+…+10)+…….+10(1+2+3+4+5+….+10)
S=(1+2+3+4+5+6+7+8+9+10)(1+2+3+4+5+6+7+8+9+10)
S=((10*11)/2)*((10*11)/2)
S=(110*110)/4
That is the sum comes out to be S
Average is S/100 since there are total 100 numbers
This implies
A=(110*110)/(4*100)
A=121/4
Which is your required answer
I hope my answer is helpful
Thank you.
Answered by
0
these are the multiples of no. up to 10
I hope it will help u
I hope it will help u
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