Math, asked by satishpratibha25, 8 days ago

Multiples of 7 are written next to each other 714212835 . Find 2020th digit

Answers

Answered by manaskm2005
0

Answer:Very Simple !

Count of number of various digit multiples of 7

(1) one digit ~ 7 i.e. only 1 ~ total digits written 1

(2) 2 digit ~ 14 to 98 i.e. 13 ~ total digits 2*13 = 26

(3) 3 digit ~ 105 to 994 i.e. 128 ~ digits 3*128 = 384

Upto 994 , number of total digits written is 411

We want 2020th digit & that will be 2020 — 411 = 1609 th digit after this now ! & that will be found in 403 th 4 digit number as 402 * 4 = 1608 digits hereafter will be written for next 402 four digit numbers & our required 1609 th digit will be 1st digit of our 403 th four digit number !

That 403 th four digit number is ~ Last 3 digit number 994 + 7*403 = 3815

3 is the 1st digit of this 403 th four digit number written at 2020 th place in our writting of 7 multiples !

So answer is digit 3

Answered by amitnrw
0

Given : Multiples of 7 are written next to each other 714212835...

To Find : 2020th digit.

Solution:

one digit number  7   one number = 1 digit

two digit numbers

14  to  98     13 numbers = 26  digits

three digit numbers

105  to  994  , 128  number  , 384 digits

384 + 26 + 1  = 411 Digits

for 2020 th digit  

2020 - 411  =  1609  Digits

1609  = 402 * 4  + 1    

Hence 402 ,  4 digit numbers and 1st digit of 403rd 4 digit number

4 digit numbers  starts from 1001

1001 + (403 - 1) 7

= 3815

3815  first digit is  3

Hence  2020th digit. is 3

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