Question

Multiplication of (2x-y+3) and (2x-y-3)

Answer 1

Answer:

2x-y-3=0 4x+y-3=0 [GIVEN]

here a1 =2,b1=-1,c1=-3

also A2=4,b2=1,c2=-3

by cross multiplication

x/b1c2-b2c1=y/a2c1-a1c2 =1/a1b2-a2b1

x/-1[-3]-[-3][1]=y/[-3][4]-[-3][2]

=1/[2][1]-[4][-1]

x/3+3=y/-12+6=1/2+4

X/6=Y/-6=1/6

X/6=1/6

Y/6=-1/6

X=1 AND Y=-1

HENCE SOLVED

Step-by-step explanation:

Answer 2

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