Question

Multiplication of {(⅕)m+ 2n} by {(⅔)m- n} is ​

Answer 1

Answer:

Correct option is

C

50

1

Now

6

m

×10

n+2

×15

m

2

m+1

×3

2m−n

×5

m+n

×6

n

=

(2×3)

m

×(2×5)

n+2

×(3×5)

m

2

m

×2

1

×

3

n

3

2m

×5

m

×5

n

×(2×3)

n

=

3

n

×(2×3)

m

×(2×5)

n+2

×(3×5)

m

2

m

×2

1

×3

2m

×5

m

×5

n

×(2×3)

n

=

3

n

×2

m

×3

m

×2

n+2

×5

n+2

×3

m

×5

m

2

m

×2

1

×3

2m

×5

m

×5

n

×2

n

×3

n

=

3

m+m

2×3

2m

×5

n−(n+2)

×2

n−(n+2)

=

3

2m

2×3

2m

×5

−2

×2

−2

=2×5

−2

×2

−2

=2×(5×2)

−2

Correct option is

C

50

1

Now

6

m

×10

n+2

×15

m

2

m+1

×3

2m−n

×5

m+n

×6

n

=

(2×3)

m

×(2×5)

n+2

×(3×5)

m

2

m

×2

1

×

3

n

3

2m

×5

m

×5

n

×(2×3)

n

=

3

n

×(2×3)

m

×(2×5)

n+2

×(3×5)

m

2

m

×2

1

×3

2m

×5

m

×5

n

×(2×3)

n

=

3

n

×2

m

×3

m

×2

n+2

×5

n+2

×3

m

×5

m

2

m

×2

1

×3

2m

×5

m

×5

n

×2

n

×3

n

=

3

m+m

2×3

2m

×5

n−(n+2)

×2

n−(n+2)

=

3

2m

2×3

2m

×5

−2

×2

−2

=2×5

−2

×2

−2

=2×(5×2)

−2

=

25×4

2

=

50

1

=

25×4

2

=

50

1

Step-by-step explanation:

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