Question

Multiply :

1. (12x² - 4x + 5) by 8x³
2. (3a³x³ - 4ay² + 7a²y) by - 4x²ya²

Need ASAP!
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Answer 1

$\huge \sf {\orange {\underline {\pink{\underline{Answer :-}}}}}$

→$\left(12x^2-4x+5\right)\cdot \:8x^3$

$=8x^3\left(12x^2-4x+5\right)$

$=8\cdot \:12x^3x^2-8\cdot \:4x^3x+8\cdot \:5x^3$

$=96x^5-32x^4+40x^3$

→$\left(3a^3x^3-4ay^2+7a^2y\right)\left(-4\right)x^2ya^2$

$=\left(-4\right)y\left(-4ay^2+7a^2y+3a^3x^3\right)\left(ax\right)^2$

$=-\left(3a^3x^3-4ay^2+7a^2y\right)\cdot \:4\left(xa\right)^2y$

$=-4a^2x^2y\left(-4ay^2+7a^2y+3a^3x^3\right)$

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Answer 2

Answer:

$(12x2−4x+5)⋅8x3 \\ </p><p>=8x^3\left(12x^2-4x+5\right)=8x3(12x2−4x+5) \\ </p><p>=8\cdot \:12x^3x^2-8\cdot \:4x^3x+8\cdot \:5x^3=8⋅12x3x2−8⋅4x3x+8⋅5x3 \\ </p><p>=96x^5-32x^4+40x^3=96x5−32x4+40x3 \\ </p><p>\left(3a^3x^3-4ay^2+7a^2y\right) \\ \left(-4\right)x^2ya^2(3a3x3−4ay2+7a2y)(−4)x2ya2 \\ </p><p>=\left(-4\right)y\left(-4ay^2+7a^2y+3a^3x^3\right) \\ \left(ax\right)^2=(−4)y(−4ay2+7a2y+3a3x3)(ax)2 \\ </p><p>=-\left(3a^3x^3-4ay^2+7a^2y\right)\cdot \:4\left(xa\right)^2y=−(3a3x3−4ay2+7a2y)⋅4(xa)2y \\ </p><p>=-4a^2x^2y\left(-4ay^2+7a^2y+3a^3x^3\right) \\ =−4a2x2y(−4ay2+7a2y+3a3x3)</p><p>$

Step-by-step explanation:

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