Question

multiply {1/5x^2+2/5} and { 2x^2-3xy+5/3}​

Answer 1

Answer:

$( \frac{1}{5} {x}^{2} + \frac{2}{5} ) \times (2 {x}^{2} - 3xy + \frac{5}{3} ) \\ = ( \frac{2}{5} {x}^{4} - \frac{3}{5} {x}^{3} y + \frac{1}{3} {x}^{2} + \frac{4}{5} {x}^{2} - \frac{6}{5} xy + \frac{2}{3} ) \\ = ( \frac{2}{5} {x}^{4} - \frac{3}{5} {x}^{3} y + \frac{17}{15} {x}^{2} - \frac{6}{5} xy + \frac{2}{3} ) \\ = \frac{(6 {x}^{4} - 9 {x}^{3}y + 17 {x}^{2} - 18xy + 10) }{15} \\ you \: can \: simplify \: it \: as \: well \\ = \frac{(6 {x}^{2} - 9xy + 5)( {x}^{2} + 2) }{15}$