Question

Multiply
2^3 , 2x^2y and (- 5xy^2)​

Answer 1

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Answer 2

Answer:

$[2^3 \times 2x^2y \times (- 5xy^2)]= -80x^3y^3$

Step-by-step explanation:

$[2^3 \times 2x^2y \times (- 5xy^2)]\\= 8 \times 2x^2y\times (- 5xy^2)\\= 16 x^2y\times (- 5xy^2)\\= -80x^3y^3)$