Question

MULTIPLY (2a+3b) and (3a+4b)​

Answer 1

Answer:

answer in attachment

Step-by-step explanation:

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Answer 2

Given: $(2a+3b) \ and \ (3a+4b)$

We have to multiply the above data.

• As we know that the multiplication is a method to get the product by multiplying two or more values.
• Multiplication is denoted by the symbol(x).

We are solving in the following way:

We have,

$(2a+3b) \ and \ (3a+4b)$

We will multiply the terms of the first bracket with the terms of the second bracket.

$=>(2a+3b) \times (3a+4b)\\=>2a\times3a+2a\times4b+3b\times3a+3b\times4b\\=>6a^2+8ab+9ba+12b^2$

simplifying the above:

$=>6a^2+8ab+9ba+12b^2\\=>6a^2+17ab+12b^2$

Hence, we get the solution is$6a^2+17ab+12b^2$.