Question

Multiply: 2abc and (-4ab – 3bc – 2ac)​

Answer 1

Answer:

      ,-14

Step-by-step explanation:

Answer 2

2abc* (-4ab – 3bc – 2ac)​ = -8a²b²c - 6ab²c² - 4a²bc².

Given:

2abc and (-4ab – 3bc – 2ac)​

To find:

Multiplication of the algebraic expression

Solution:

We have to multiply 2abc by each of the polynomial starting from -4ab along with its sign.

2abc* (-4ab – 3bc – 2ac)​

We will multiply 2abc by each integer with their sign separately and at the end we will add them without changing their signs.

= (2abc * -4ab) - (3bc * 2abc) - (2abc*2ac)

= -8a²b²c - 6ab²c² - 4a²bc²

So, this will be our answer as they cannot be added or simplified any further.

The power of variables is the number of times they are in the expression.

Hence, the answer is -8a²b²c - 6ab²c² - 4a²bc².

#SPJ2