Question

Multiply (2p + q) (2p²– 3q + 1)​

Answer 1

Step-by-step explanation:

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(a + b) × (c – d) = a × (c – d) + b × (c – d)

= (a × c – a × d) + (b × c – b × d)

= ac – ad + bc – bd

Let, a= 3p2, b= q2, c= 2p2, d= 3q2

Now, = 3p2× (2p2 – 3q2) + q2 × (2p2 – 3q2)

= [(3p2× 2p2) + (3p2× -3q2)] + [(q2 × 2p2) + (q2 × -3q2)]

= [6p4 – 9p2q2 + 2q2p2 – 3q4)]

= [6p4 – 7p2q2 – 3q4]

Hope it helpful..., ☃️⚡️

#Somya Here

Answer 2

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GIVEN :-

(2p + q) (2p²– 3q + 1)

TO FIND :-

Multiply (2p + q) (2p²– 3q + 1)

SOLUTION :-

(2p + q) (2p²– 3q + 1)

We Have to Multiply this Binomial Number,

(2p + q) (2p²– 3q + 1)

= 2p( 2p²- 3q + 1 )+q( 2p² - 3q + 1 )

= 4p³ - 6pq + 2p + 2p²q - 3q² + q

= 6p⁴ - 6pq + 2p²q - 2q

HENCE,

6p⁴ - 6pq + 2p²q - 2q is The Correct Answer.

• I Hope it's Helpful.