Multiply:-
2pq + 3p²q and 7p²q + 4
Answers
Answered by
0
Answer:
(2pq+3q2)×(3pq−2q2)
=2pq(3pq−2q2)+3q2(3pq−2q2)
=6p2q2−4pq3+9pq3−6q4
=6p2q2+5pq3−6q4
Step-by-step explanation:
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Answered by
1
Answer:
14p^3q² + 8pq + 21p^4q^2 + 12p^2q
Step-by-step explanation:
(2pq + 3p²q)(7p²q + 4)
=(2pq)(7p²q) + (2pq)(4) + (3p²q)(7p²q) + (3p²q)(4)
=14p^3q² + 8pq + 21p^4q^2 + 12p^2q
Hope this helps :)
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