Math, asked by tanyachannel05, 2 months ago

Multiply:-
2pq + 3p²q and 7p²q + 4

Answers

Answered by klsharma1441993
0

Answer:

(2pq+3q2)×(3pq−2q2)

=2pq(3pq−2q2)+3q2(3pq−2q2)

=6p2q2−4pq3+9pq3−6q4

=6p2q2+5pq3−6q4

Step-by-step explanation:

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Answered by prathibarr
1

Answer:

14p^3q² + 8pq + 21p^4q^2 + 12p^2q

Step-by-step explanation:

(2pq + 3p²q)(7p²q + 4)

=(2pq)(7p²q) + (2pq)(4) + (3p²q)(7p²q) + (3p²q)(4)

=14p^3q² + 8pq + 21p^4q^2 + 12p^2q

Hope this helps :)

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