multiply 2x 2y by -4x3 y2
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Answer:
Multiplying term by term and then adding,
(2x
2
−3xy+y
2
)×(2y
2
−xy−x
2
)
=2x
2
(2y
2
−xy−x
2
)−3xy(2y
2
−xy−x
2
)+y
2
(2y
2
−xy−x
2
)
=4x
2
y
2
−2x
3
y−2x
4
−6xy
3
+3x
2
y
2
+3x
3
y+2y
4
−xy
3
−x
2
y
2
=6x
2
y
2
−x
3
y−7xy
3
+2y
4
−2x
4
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