multiply (2x^3-5x^2-x+7) by (3-2x+4x^2)
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Answered by
9
Answer:
8x^5-24x^4+12x^3+15x^2
Step-by-step explanation:
= (2x^3-5x^2-x+7) * (3-2x+4x^2)
= 2x^3(3-2x+4x^2) - 5x^2(3-2x+4x^2) - x(3-2x+4x^2)+7(3-2x+4x^2)
= (6x^3-4x^4+8x^5) - (15x^2-10x^3+20x^4) - (3x-2x^2+4x^3) + (21-14x+28x^2)
= 6x^3-4x^4+8x^5-15x^2+10x^3-20x^4-3x+2x^2-4x^3+21-14x+28x^2
= 6x^3+10x^3-4x^3-4x^4-20x^4+8x^5-15x^2+2x^2+28x^2
= 12x^3-24x^4+8x^5+15x^2
= 8x^5-24x^4+12x^3+15x^2
Answered by
2
8x⁵-24x⁴+12x³+15x²
(2x^3-5x^2-x+7) by (3-2x+4x^2)
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