Question

multiply ( 2x²+y) and ( 3x–y²)​

Answer 1

Answer:

=4x³y-9xy³-2xz+3yz

Step-by-step explanation:

(2x²y+3xy²-z) × (2x-3y)

=2x(2x²y+3xy²-z) -3y(2x²y+3xy²-z)

=4x³y+6x²y²-2xz -6x²y²-9xy³+3yz

=4x³y-9xy³-2xz+3yz

Answer 2

$\large\red{\sf{⇝(2x ^{2} + y) \times (3x - y ^{2} )}}$

• Multiply each term in the first parentheses by each term in the second parentheses (FOIL)

$\large\orange{\sf{⇝2x ^{2} \times 3x - 2x ^{2} y ^{2} + 3xy - y \times y ^{2} }}$

• Calculate the product

$\large\green{\sf{⇝6x ^{3} - 2 x^{2} y ^{2} + 3xy - y ^{3} }}$