multiply (2x³+ 3y)×(x+y²)
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2
Answer:
2 + 3
+ 2x³y² + 3xy
Step-by-step explanation:
(2x³+ 3y)×(x+y²)
=> x * ( 2x³+ 3y ) + y² (2x³+ 3y)
=> (2+ 3xy) + ( 2x³y² + 3
)
=> 2 + 3
+ 2x³y² + 3xy
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