multiply (2y+3)×(4y-2) give answer in step by step
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Answer:
Given:
(2y+3) × (4y-2)
= 8y²-4y +12y -6
=8y²+8y-6
If you want to find out the roots it will be :
8y²+8y-6
Here, a=8 , b=8 , c=-6
=-b±√b²-4ac/2a
=-8±√(8) ²-4(8) (-6) /2*8
=-8±√64+192/16
=-8±√256/16
=-8±√(16)²/16
=-8±16/16
so, y=-8+16/16 or y=-8-16/16
=8/16=1/2 y= -24/16 =-3/2
so , the required roots are (1/2) and( -3/2)
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