Question

multiply :-
(2y+ 3x) (3y-2x)
​

Answer 1

We have,

$\quad \: (2y + 3x)(3y - 2x) \\ \\ = 2y(3y - 2x) + 3x(3y - 2x) \\ \\ = 6 {y}^{2} - 4xy + 3xy - 2 {x}^{2} \\ \\ = 6 {y}^{2} - xy - 2 {x}^{2}$


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Answer 2

Answer:

6y^2+5xy-6x^2

Step-by-step explanation:

2y(3y-2x)+3x(3y-2x) = 6y^2+5xy-6x^2