Question

Multiply (2y-7) and(y- 4)​

Answer 1

Step by step explanation:-

Given to multiply (2y-7) and(y- 4)

For multiplying here We cannot use any identity So, We have to multiply the terms without using identity

(2y-7)(y- 4)

$\implies$ 2y ( y - 4 ) - 7 ( y - 4 )

$\implies$ 2y (y) + 2y (-4) - 7 (y) -7 (-4)

$\implies$ 2y² - 8y - 7y + 28

$\implies$ 2y² - 15y + 28

So, the product of (2y-7) and(y- 4) is 2y² - 15y + 28

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Know more :-

(a+ b)² = a² + b² + 2ab

( a - b )² = a² + b² - 2ab

( a + b )² + ( a - b)² = 2a² + 2b²

( a + b )² - ( a - b)² = 4ab

( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca

a² + b² = ( a + b)² - 2ab

(a + b )³ = a³ + b³ + 3ab ( a + b)

( a - b)³ = a³ - b³ - 3ab ( a - b)

If a + b + c = 0 then a³ + b³ + c³ = 3abc

Answer 2

Answer:

2y² - 15y + 28

Step-by-step explanation:

(2y - 7) (y - 4) = (2y² - 8y) - (7y - 28)

= 2y² - 8y - 7y + 28

therefore = 2y² - 15y + 28

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