multiply (2y²-1)by (2y³+5y²)
Answers
Answered by
1
Answer:
4y^{5}y
5
+ 10y^{4}y
4
- 2y³ - 5y²
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, that is
2y²(2y³ + 5y²) - 1(2y³ + 5y²) ← distribute both parenthesis
= 4y^{5}y
5
+ 10y^{4}y
4
- 2y³ - 5y²
Answered by
0
Answer:
21y^14
Step-by-step explanation:
(2y^2-1) (2y^3+5y^2)
2y^2(2y^3+5y^2)-1(2y^3+5y^2)
4y^5+10y^4 -2y^3-5y^2
14y^9+7y^5
21y^14
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