Math, asked by yash59798, 9 months ago

multiply (2y²-1)by (2y³+5y²)​

Answers

Answered by ashaumesh91
1

Answer:

4y^{5}y

5

+ 10y^{4}y

4

- 2y³ - 5y²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

2y²(2y³ + 5y²) - 1(2y³ + 5y²) ← distribute both parenthesis

= 4y^{5}y

5

+ 10y^{4}y

4

- 2y³ - 5y²

Answered by manshamansha8879
0

Answer:

21y^14

Step-by-step explanation:

(2y^2-1) (2y^3+5y^2)

2y^2(2y^3+5y^2)-1(2y^3+5y^2)

4y^5+10y^4 -2y^3-5y^2

14y^9+7y^5

21y^14

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