Multiply: -2y²(3y² + 5y-2)
Answers
Answer:
-6y²+5y-2
Step-by-step explanation:
= (-2y²×3y²)+5y-2
= -6y²+5y-2
Answer:
(0 - 3y2) + 5y) - 2 = 0
Pull out like factors :
-3y2 + 5y - 2 = -1 • (3y2 - 5y + 2)
Factoring 3y2 - 5y + 2
The first term is, 3y2 its coefficient is 3 .
The middle term is, -5y its coefficient is -5 .
The last term, "the constant", is +2
Step-1 : Multiply the coefficient of the first term by the constant 3 • 2 = 6
Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is -5 .
-6 + -1 = -7
-3 + -2 = -5 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -2
3y2 - 3y - 2y - 2
Step-4 : Add up the first 2 terms, pulling out like factors :
3y • (y-1)
Add up the last 2 terms, pulling out common factors :
2 • (y-1)
Step-5 : Add up the four terms of step 4 :
(3y-2) • (y-1)
Which is the desired factorization
1 - y) • (3y - 2) = 0
product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
3y-2 = 0
Add 2 to both sides of the equation :
3y = 2
Divide both sides of the equation by 3:
y = 2/3 = 0.667