Question

multiply -3/2x^2y^3 by (2x-y)and find the answer for x=1 & y=2

Answer 1

Answer:

Step-by-step explanation:

(-3x2y2) × (x – 2y)

= (-3x2y2) × (x) – (-3x2y2) (2y)

= -3x3y2 + 6x2y3

= 6x2y3 – 3x3y2

For x = 1 and y = 2

(-3x2y2) × (x – 2y)

= (-3 × 12 × 22) × (1 – 2 × 2)

= (6 × 1 × 8) – (3 × 1 × 4)

= 48 – 12 = 36

∴ For x = 1 and y = 2, it is verified that,

(-3x2y2) × (x – 2y) = 6x2y3 – 3x3y2

Answer 2

Answer:

Step-by-step explanation:

-3/2x²y³ (2x-y)

-6x/2x²y²+3y/2x²y³

-3xy/2x²+3y³

-3/2(1)²(2)³(2(1)-(2))

-3/2(1)(8) (2-2)

-3/16

= -3/16