multiply (3/5x + 1/2y) by (5/6+4y)
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0
Answer:
Given:
3x
1
−
4y
1
+1=0;
5x
1
+
2y
1
=
15
4
Assuming,
x
1
=X,
y
1
=Y, we get
from the first equation
3
X
−
4
Y
+1=0
⇒4X−3Y+12=0 ...(1)
from the second equation
5
X
+
2
Y
=
15
4
multiply by 30 on both sides we get
⇒6X+15Y=8 ...(2)
Now, Multiplying (1) by 5 and then add (2) to it, we get
26X+52=0
⇒X=−2
⇒
x
1
=−2⇒x=−
2
1
Y=
3
4
⇒
y
1
=
3
4
⇒y=
4
3
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