Question

multiply 3(a2+2) and 4(2-b2) ​

Answer 1

solⁿ:-

{3(a²+2)} {4(2-b²)}

= (3a²+6)(8-4b²)

= 3a²(8-4b²)+6(8-4b²)

= 24a²-12a²b²+48-24b²

= 24a²-24b²-12a²b²+48

= 24(a²-b²)-12(a²b²+4)