Question

multiply (3 root 2 minus root 3 )(4root 3 minus root 2)​

Answer 1

Answer:

(3√2-√3)(4√3-√2)

=3√2(4√3-√2) - √3(4√3-√2)

=12√6 - 3(2) - 4(3) + √6

=13√6 - 6 - 12

=13√6 - 18

Answer 2

Answer:

(3 root 2 minus root 3 )(4root 3 minus root 2)​ = $13\sqrt{6} - 18$

Step-by-step explanation:

(3 root 2 minus root 3 )(4root 3 minus root 2)​

$(3\sqrt{2} - \sqrt{3} )$ × $(4\sqrt{3} - \sqrt{2} )$

$3\sqrt{2} (4\sqrt{3} - \sqrt{2}) -\sqrt{3}(4\sqrt{3} - \sqrt{2})$

$12\sqrt{6} - 3(\sqrt{2} )(\sqrt{2} ) - 4(\sqrt{3} )(\sqrt{3} ) + \sqrt{6}$

$12\sqrt{6} -6 - 12 + \sqrt{6}$

$13\sqrt{6} - 18$

A sort of radical expression, square roots, can be multiplied in the same way that you would multiply whole integers. Coefficients for square roots are sometimes included (an integer before the radical sign), however this merely adds a step to the multiplication and has no impact on how the problem is solved.

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