Question

Multiply. (3a+4)(2a-1)

Answer 1

3a(2a-1)+4(2a-1)
= 6asquare-3a+8a-4
= 6asquare+5a-4

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Answer 2

Answer:

$=6a^{2} +5a-4$

Step-by-step explanation:

• As per the data given in the question, we need to multiply $(3a+4)$ and $(2a-1)$

• On multiplying the given terms, we get

$.=(3a+4)(2a-1)$

$=(3a\times2a)-(1\times3a)+(4\times2a)-(4\times1)$

• By doing simple multiplication, we get

$=6a^{2} -3a+8a-4$

$=6a^{2} +5a-4$

Hence, on multiplying $(3a+4)$ and $(2a-1)$, we get $6a^{2} +5a-4$