multiply :- (3t³p³q³- 6t²p²q² + 12 tpq) by t⁰
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Answer:
6 multiply with √27 is equal to
√6 × √27
The given problem can be solved by expressing each term into individual roots and multiplying
√6 can be expressed as √2 × √3
√27 can be expressed as √3 × √3 × √3
= √2 × √3 × √3 × √3 × √3
= 3 × 3√2
= 9√2
Answer
√6 × √27=9√2
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