Math, asked by kumarisimaran022, 6 months ago

multiply (3x^2+5y^2) by (5x^2-3x^2) ​

Answers

Answered by magadalshivani86
1

Answer:

The value of (3x^2+5y^2)×(5x^2-3x^2) is

=3x^2(5x^2-3x^2)+5y^2(5x^2-3x^2)

=15x^4-9x^4+25x^2y^2-15x^2y^2

=6x^4+10x^2y^2

Hope it helps you

Answered by junaidmj26
0

Step-by-step explanation:

(3x^2+5y^2)(2x^2)

==> 6x^2+10y^2x^2

==>x^2(6+10y^2)=1

Similar questions