multiply (3x^2+5y^2) by (5x^2-3x^2)
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Answered by
1
Answer:
The value of (3x^2+5y^2)×(5x^2-3x^2) is
=3x^2(5x^2-3x^2)+5y^2(5x^2-3x^2)
=15x^4-9x^4+25x^2y^2-15x^2y^2
=6x^4+10x^2y^2
Hope it helps you
Answered by
0
Step-by-step explanation:
(3x^2+5y^2)(2x^2)
==> 6x^2+10y^2x^2
==>x^2(6+10y^2)=1
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