Question

Multiply (3x^2+y^2) and (2x^2-3y^2) using column method​

Answer 1

let us we solve,

= (3x2 + y2) × (2x2 + 3y2)

= 3x2 × (2x2 + 3y2) + y2 × (2x2 + 3y2)

= 6x4 + 9x2y2 + 2x2y2 + 3y4 = 6x4 + 11x2y2 + 3y4

thanks me later first

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