Math, asked by mzeestorm2006, 8 months ago

multiply 3x^2y and -2xy^2.
verify the product for x=1
and y=2​

Answers

Answered by pushpakumari7150573
2

Answer:

-6x³y³

Step-by-step explanation:

(3×-2)(x²y×xy²)

-6x³y³

Verification....

Putting the value of x&y

3×1²×2×-2×1×2²

3×1×2×-2×1×4

-48

Putting the value of x &y

-6×1³×2³

-6×1×8

-48

-48= -48

Verified

Mark this answer as BRAINLIEST answer !

Answered by akshitamodi001
1

ANSWER : -6x^3y^3

Step-by-step explanation:

(Using Horizontal Method)

3x^2y × -2xy^2 = {3 × (-2)} × {x^2y × xy^2}

= -6x^(2+1) y^(1+2)

= -6x^3y^3.

Verification : Given _ x=1 &y=2

-6x^3y^3 = -6(1^3)(2^3)

= -6(1)(8)

= -48.

Hope it helps u...

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Have a good day :)

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