multiply (3x+7)(2x^2-3x+4)
Answers
Answered by
0
Answer:
(3x+7) (2x^2-3x+4)
=3x(2x^2-3x+4) +7(2x^2-3x+4)
=6x^3-9x^2+12x+14x^2-21x+28
=6x^3+5x^2-9x+28
Similar questions