Math, asked by akashjha3228, 2 months ago

Multiply (3x2 – 4xy + 2y2 ) by (2x – y) and find the value of the product, when x = -1 and y =2.

Answers

Answered by Ravina
1

Answer:

6x³ - 11x²y + 8xy² - 2y³ = -76

Step-by-step explanation:

(3x² – 4xy + 2y²) x (2x – y)

= 2x(3x² – 4xy + 2y²) - y(3x² – 4xy + 2y²)

= 2x(3x²) - 2x(4xy) + 2x(2y²) - {y(3x²) - y(4xy) + y(2y²)}

= 6x³ - 8x²y + 4xy² - {3x²y - 4xy² + 2y³}

= 6x³ - 8x²y + 4xy² - 3x²y + 4xy² - 2y³

= 6x³ - 8x²y - 3x²y + 4xy² + 4xy² - 2y³

= 6x³ - 11x²y + 8xy² - 2y³

When x = -1 and y = 2,

6x³ - 11x²y + 8xy² - 2y³

= 6(-1)³ - 11(-1)²(2) + 8(-1)(2)² - 2(2)³

= 6(-1) - 11(1)(2) + 8(-1)(4) - 2(8)

= -6 - 22 - 32 - 16

= -76

Answered by avishikhandelwal
0

Answer:

6x³ - 11x²y + 8xy² - 2y³ = -76

Step -by-step explanation:

(3x² – 4xy + 2y²) x (2x – y)

= 2x(3x² – 4xy + 2y²) - y(3x² – 4xy + 2y²)

= 2x(3x²) - 2x(4xy) + 2x(2y²) - {y(3x²) - y(4xy) + y(2y²)}

= 6x³ - 8x²y + 4xy² - {3x²y - 4xy² + 2y³}

= 6x³ - 8x²y + 4xy² - 3x²y + 4xy² - 2y³

= 6x³ - 8x²y - 3x²y + 4xy² + 4xy² - 2y³

= 6x³ - 11x²y + 8xy² - 2y³

When x = -1 and y = 2,

6x³ - 11x²y + 8xy² - 2y³

= 6(-1)³ - 11(-1)²(2) + 8(-1)(2)² - 2(2)³

= 6(-1) - 11(1)(2) + 8(-1)(4) - 2(8)

= -6 - 22 - 32 - 16

= -76

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