Question

multiply (-3xy^4/14) × (7x^3y)​

Answer 1

Given expression is $(-3xy^{4} /14)$ $\times$$(7x^{3}y)$,

We have to solve given expression,

Dividing $7$ and $14$ by $7$

we get the expression is $\frac{-3xy^{4} }{2} \times x^{3} y$

multiplying $x$ with $x^{3}$ and $y$  with $y^{3}$ and we get $x^{4}$ and $y^{5}$ respectively.

We get, $(-3xy^{4} /14)$$\times$$(7x^{3}y)$$=\frac{-3x^{4}y^{5} }{2}$

Therefore, $\frac{-3x^{4}y^{5} }{2}$ is a required answer.

Answer 2

Answer:

The answer is = $(-3/2)x^{4} y^{5}$

Step-by-step explanation:

(-3xy^4/14) × (7x^3y)​

= (-3)×x×y^4/14×7×x^3×y)

=(-3)×7×/14×x×x^3×y^4×y

=(-3/2)×x^(1+3)×y^(4+1)

=(-3/2)×x^4×y^5

$=(-3/2)x^{4} y^{5}$